# What is the equation of the line that passes through #(-1,1) # and is perpendicular to the line that passes through the following points: #(13,1),(-2,3) #?

Now, we use the Slope-Point Formula for the reqd. line, known to

Thus, the eqn. of the reqd. line, is,

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To find the equation of the line passing through (-1,1) and perpendicular to the line passing through (13,1) and (-2,3), we first find the slope of the given line using the formula:

[ m = \frac{y_2 - y_1}{x_2 - x_1} ]

where ((x_1, y_1) = (13,1)) and ((x_2, y_2) = (-2,3)).

Then, we find the negative reciprocal of this slope to get the slope of the perpendicular line.

Next, we use the point-slope form of a line:

[ y - y_1 = m(x - x_1) ]

where ((x_1, y_1) = (-1,1)) and (m) is the slope of the perpendicular line.

We substitute the values into the equation to find the equation of the perpendicular line.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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